Event cube..how?

If waking up early on my off days always gives me an insanity talisman, I am never going to wake up after 8:30

 

I hate you so much.

 

So tru,so unfair for working class ,QQ!

 

Oh, you are right.
I included boxing because you admited that it is possible to win with using a macro.

Ok, let's see it again: winning any 2 of the events using 1 char: (1-(499/500)^27)*(1-(499/500)^26) that is about 0,27%. Still doesn't look impossible to win twice.

 

The probability that someone wins twice is much higher than the probability that 1 particular individual wins twice tho.

If I apply this formula that i found on wikipedia for the probability of finding the same result twice when taking 28 ( number of winners) random elements in an ensemble of 500 ( number of total players supposedly participating) :

P(28) ~ 1- exp ( -(28*27)/(2*500)) = 0, 53 . (This is an approximated value)

So if i'm not fully wrong, it's actually quite likely that 1 person will win twice, assuming that everyone plays on every events.

I'm sorry, could only find the article in french, see " generalisation " paragraph : https://fr.wikipedia.org/wiki/Paradoxe_des_anniversaires

 

It reminds me a funny experiment. If you put 30 people in a room, you've more than 50% chance to have 2 ppl having the same birthday

 

Thats exactly what i linked

 

It's not like that, if you put 31 people in same room, 2 of them at least will have birthday the same day because 31/30 (if we count 1 month as 30) > 1